Evaluate the following limit : lim(x→π/2) (√(2 - sin x) - 1)/(π/2 - x)^2 - Sarthaks eConnect | Largest Online Education Community
![Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/fig_52a4944619864405640501.png)
Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com
![Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com](https://homework.study.com/cimages/multimages/16/fig_52c2250900925405944793.png)
Sketch the graph of y = - 2 sin (x - pi / 2) + 3 over the interval [0, 2 pi] by comparing it to the graph of y = sin x. | Homework.Study.com
Evaluate the following limit : lim(x→π/2) (√(2 - sin x) - 1)/(π/2 - x)^2 - Sarthaks eConnect | Largest Online Education Community
![Let f(x)={-2sinx for -pi<=x <=-pi/2 a sin x+ b for - pi/2 < x < pi/2.cos x for pi/2 <= x <= pi if f is continuous on [-pi, pi).then find the Let f(x)={-2sinx for -pi<=x <=-pi/2 a sin x+ b for - pi/2 < x < pi/2.cos x for pi/2 <= x <= pi if f is continuous on [-pi, pi).then find the](https://d10lpgp6xz60nq.cloudfront.net/ss/web/99525.jpg)