![Transcendental vs. Algebraic Numbers | Concept, Equations & Examples - Video & Lesson Transcript | Study.com Transcendental vs. Algebraic Numbers | Concept, Equations & Examples - Video & Lesson Transcript | Study.com](https://study.com/cimages/multimages/16/screen_shot_2022-02-17_at_9.14.11_pm3302385287597831652.png)
Transcendental vs. Algebraic Numbers | Concept, Equations & Examples - Video & Lesson Transcript | Study.com
Fermat's Library on Twitter: "Following yesterday's tweet, here's a proof that e^π is transcendental. https://t.co/O8yULNz74P" / Twitter
![transcendental numbers - Transcendence of $\pi+\log\alpha$ and $e^{\alpha\pi+\beta}$ - Mathematics Stack Exchange transcendental numbers - Transcendence of $\pi+\log\alpha$ and $e^{\alpha\pi+\beta}$ - Mathematics Stack Exchange](https://i.stack.imgur.com/il99A.jpg)
transcendental numbers - Transcendence of $\pi+\log\alpha$ and $e^{\alpha\pi+\beta}$ - Mathematics Stack Exchange
![Priyanka (Astrology Guidance) on Twitter: "Euler's identity is extremely special because it combines centuries of mathematics. i= imaginary number e, Pi = transcendental and irrational number 0,1: whole and natural numbers. It Priyanka (Astrology Guidance) on Twitter: "Euler's identity is extremely special because it combines centuries of mathematics. i= imaginary number e, Pi = transcendental and irrational number 0,1: whole and natural numbers. It](https://pbs.twimg.com/media/EV0Rt_HUMAEvAeZ.png)
Priyanka (Astrology Guidance) on Twitter: "Euler's identity is extremely special because it combines centuries of mathematics. i= imaginary number e, Pi = transcendental and irrational number 0,1: whole and natural numbers. It
MathType - The Gelfond constant, e to the power of pi, is known to be a transcendental number (it isn't the solution to any polynomial equation with integer coefficients) thanks to the
![MathType on Twitter: "But wait, Lindemann's Theorem just told us that if a number is algebraic then e to the power of that number must be algebraically independent over the rationals (which MathType on Twitter: "But wait, Lindemann's Theorem just told us that if a number is algebraic then e to the power of that number must be algebraically independent over the rationals (which](https://pbs.twimg.com/media/D39V-FtWwAA-T5S.jpg)